Anonymous user
Random numbers: Difference between revisions
m
→{{header|Lingo}}
m (Lingo added) |
|||
Line 1,121:
=={{header|Lingo}}==
<lang Lingo>----------------------------------------
-- Returns a random float value x in range 0..1
----------------------------------------
Line 1,128 ⟶ 1,127:
n = random(the maxinteger)-1
return n / float(the maxinteger-1)
end</lang>
<lang Lingo>normal = []
repeat with i = 1 to 1000
normal.add(1 + sqrt(-2 * log(randf())) * cos(2 * PI * randf()) / 2)
end repeat</lang>
=={{header|lua}}==
| |||