Random Latin squares: Difference between revisions

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<pre>
<pre>
let β=lN2p [|0;N 4;N 3;N 2|] [|0..4|] in Seq.item (N 55) (normLS 5) |> List.map(lN2p [|N 5;N 4;N 3;N 2|]) |> List.permute(fun n->β.[n]) |> List.iter(printfn "%A")
[|5; 3; 1; 4; 2|]
[|5; 3; 1; 4; 2|]
[|1; 4; 5; 2; 3|]
[|1; 4; 5; 2; 3|]