Primes whose sum of digits is 25: Difference between revisions
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(Created page with "{{Draft task}} ;Task: Show primes which sum of digits is '''25''' <br> Let '''0 < n < 5000''' =={{header|Ring}}== <lang ring> load "stdlib.ring" row = 0 limit1 = 25 limit2...") |
(Added phix and stretch goal) |
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Show primes which sum of digits is '''25''' |
Show primes which sum of digits is '''25''' |
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<br> Let '''0 < n < 5000''' |
<br> Let '''0 < n < 5000''' |
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;Stretch goal |
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Show the total number of all such primes that do not contain any zeroes. |
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=={{header|Phix}}== |
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<lang Phix>function sum25(integer p) return sum(sq_sub(sprint(p),'0'))=25 end function |
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sequence res = filter(get_primes_le(5000),sum25) |
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string r = join(shorten(apply(res,sprint),"",4)) |
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printf(1,"%d sum25 primes less than 5000 found: %s\n",{length(res),r})</lang> |
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{{out}} |
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<pre> |
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17 sum25 primes less than 5000 found: 997 1699 1789 1879 ... 4597 4759 4957 4993 |
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</pre> |
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Stretch goal |
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<lang Phix>include mpfr.e |
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atom t0 = time(), t1 = time()+1 |
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mpz pz = mpz_init(0) |
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function sum25(string p, integer rem, res=0) |
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if rem=0 then |
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if find(p[$],"1379") then -- (saves 13s) |
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mpz_set_str(pz,p) |
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if mpz_prime(pz) then |
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res += 1 |
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if time()>t1 then |
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progress("%d, %s...",{res,p}) |
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t1 = time()+1 |
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end if |
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end if |
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end if |
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else |
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for i=1 to min(rem,9) do |
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res = sum25(p&'0'+i,rem-i,res) |
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end for |
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end if |
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return res |
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end function |
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printf(1,"There are %,d sum25 primes that contain no zeroes\n",sum25("",25)) |
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?elapsed(time()-t0)</lang> |
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{{out}} |
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<pre> |
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There are 1,525,141 sum25 primes that contain no zeroes |
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"1 minute and 27s" |
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</pre> |
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=={{header|Ring}}== |
=={{header|Ring}}== |