Power set: Difference between revisions

(K version added)
Line 524:
}
</lang>
 
=={{header|Clojure}}==
<lang Clojure>(use '[clojure.contrib.combinatorics :only [subsets] ])
 
(def S #{1 2 3 4})
 
user> (subsets S)
(() (1) (2) (3) (4) (1 2) (1 3) (1 4) (2 3) (2 4) (3 4) (1 2 3) (1 2 4) (1 3 4) (2 3 4) (1 2 3 4))</lang>
 
=={{header|Common Lisp}}==
Anonymous user