Power set: Difference between revisions

Combinations([1, 2, 3]);

# [ [ ], [ 1 ], [ 1, 2 ], [ 1, 2, 3 ], [ 1, 3 ], [ 2 ], [ 2, 3 ], [ 3 ] ]

# Note that it handles duplicates

Combinations([1, 2, 3, 1]);