Population count: Difference between revisions

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{{trans|Python}}
 
<syntaxhighlight lang="11l">Fprint((0.<30).map(i -> bits:popcount(nInt64(3) ^ i)))
R bin(n).count(‘1’)
 
print((0.<30).map(i -> popcount(Int64(3) ^ i)))
 
[Int] evil, odious
V i = 0
L evil.len < 30 | odious.len < 30
V p = bits:popcount(i)
I (p % 2) != 0
odious.append(i)
Line 1,017 ⟶ 1,014:
return popul
end function</syntaxhighlight>
 
{{out}}
==={{header|Run BASIC}}===
<pre>Same as Yabasic entry.</pre>
<syntaxhighlight lang="vb">function tobin$(num)
bin$ = ""
if num = 0 then bin$ = "0"
while num >= 1
num = num / 2
X$ = str$(num)
D$ = "": F$ = ""
for i = 1 to len(X$)
L$ = mid$(X$, i, 1)
if L$ <> "." then
D$ = D$ + L$
else
F$ = F$ + right$(X$, len(X$) - i)
exit for
end if
next i
if F$ = "" then B$ = "0" else B$ = "1"
bin$ = bin$ + B$
num = val(D$)
wend
B$ = ""
for i = len(bin$) to 1 step -1
B$ = B$ + mid$(bin$, i, 1)
next i
tobin$ = B$
end function
 
function population(number)
popul = 0
'digito$ = tobin$(number)
'print tobin$(number)
for i = 1 to len(tobin$(number))
popul = popul + val(mid$(tobin$(number), i, 1))
next i
population = popul
end function
 
sub evilodious limit, tipo
i = 0
cont = 0
while 1
eo = (population(i) mod 2)
if (tipo and eo = 1) or ((not(tipo) and not(eo)) = 1) then
cont = cont + 1: print i; " ";
end if
i = i + 1
if cont = limit then exit while
wend
end sub
 
print "Pop cont (3^x): ";
for i = 0 to 14
print population(3 ^ i); " ";
next i
 
print
print "Evil numbers: ";
call evilodious 15, 0
 
print
print "Odious numbers: ";
call evilodious 15, 1
end</syntaxhighlight>
 
=={{header|BCPL}}==
Line 1,643 ⟶ 1,708:
 
</syntaxhighlight>
 
=={{header|EasyLang}}==
<syntaxhighlight>
func popcnt x .
while x > 0
r += x mod 2
x = x div 2
.
return r
.
proc show3 . .
write "3^n:"
bb = 1
for i = 1 to 30
write " " & popcnt bb
bb *= 3
.
print ""
.
proc show s$ x . .
write s$
while n < 30
if popcnt i mod 2 = x
n += 1
write " " & i
.
i += 1
.
print ""
.
show3
show "evil:" 0
show "odious:" 1
</syntaxhighlight>
 
 
=={{header|Elixir}}==
Line 1,940 ⟶ 2,040:
 
{{FormulaeEntry|page=https://formulae.org/?script=examples/Population_count}}
 
'''Solution'''
 
Fōrmulæ has an integrated expression BitCount that counts the number of 1's of the binary representation of the number.
 
However, a function can also be written, as follows:
 
[[File:Fōrmulæ - Population count 01.png]]
 
'''Case 1. Display the pop count of the 1st thirty powers of 3'''
 
[[File:Fōrmulæ - Population count 02.png]]
 
[[File:Fōrmulæ - Population count 03.png]]
 
'''Case 2. Display the 1st thirty evil numbers'''
 
We need first a function to calculate the first numbers whose population count satisfies a given condition, passed as a lambda expression:
 
[[File:Fōrmulæ - Population count 04.png]]
 
[[File:Fōrmulæ - Population count 05.png]]
 
[[File:Fōrmulæ - Population count 06.png]]
 
'''Case 3. Display the 1st thirty odious numbers'''
 
[[File:Fōrmulæ - Population count 07.png]]
 
[[File:Fōrmulæ - Population count 08.png]]
 
=={{Header|FreeBASIC}}==
Line 3,045 ⟶ 3,175:
0 3 5 6 9 10 12 15 17 18 20 23 24 27 29 30 33 34 36 39 40 43 45 46 48 51 53 54 57 58
1 2 4 7 8 11 13 14 16 19 21 22 25 26 28 31 32 35 37 38 41 42 44 47 49 50 52 55 56 59 ok
</pre>
 
=={{header|Ol}}==
<syntaxhighlight lang="scheme">
(define (popcount n)
(let loop ((n n) (c 0))
(if (= n 0)
c
(loop (>> n 1)
(if (eq? (band n 1) 0) c (+ c 1))))))
(print (popcount 31415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253))
 
 
(define thirty 30)
 
(display "popcount:")
(for-each (lambda (i)
(display " ")
(display (popcount (expt 3 i))))
(iota thirty 0))
(print)
 
(define (evenodd name test)
(display name) (display ":")
(for-each (lambda (i)
(display " ")
(display i))
(reverse
(let loop ((n 0) (i 0) (out '()))
(if (= i thirty)
out
(if (test (popcount n))
(loop (+ n 1) (+ i 1) (cons n out))
(loop (+ n 1) i out))))))
(print))
 
(evenodd "evil" even?)
(evenodd "odius" odd?)
</syntaxhighlight>
{{out}}
<pre>
159
popcount: 1 2 2 4 3 6 6 5 6 8 9 13 10 11 14 15 11 14 14 17 17 20 19 22 16 18 24 30 25 25
evil: 0 3 5 6 9 10 12 15 17 18 20 23 24 27 29 30 33 34 36 39 40 43 45 46 48 51 53 54 57 58
odius: 1 2 4 7 8 11 13 14 16 19 21 22 25 26 28 31 32 35 37 38 41 42 44 47 49 50 52 55 56 59
</pre>
 
Line 4,041 ⟶ 4,216:
odious: 1 2 4 7 8 11 13 14 16 19 21 22 25 26 28 31 32 35 37 38 41 42 44 47 49 50 52 55 56 59 </pre>
 
=={{header|SETL}}==
<syntaxhighlight lang="setl">program population_count;
print([popcount(3**n) : n in [0..29]]);
print([n : n in [0..59] | evil n]);
print([n : n in [0..59] | odious n]);
 
op evil(n);
return even popcount n;
end op;
 
op odious(n);
return odd popcount n;
end op;
 
op popcount(n);
return +/[[n mod 2, n div:=2](1) : until n=0];
end op;
end program;</syntaxhighlight>
{{out}}
<pre>[1 2 2 4 3 6 6 5 6 8 9 13 10 11 14 15 11 14 14 17 17 20 19 22 16 18 24 30 25 25]
[0 3 5 6 9 10 12 15 17 18 20 23 24 27 29 30 33 34 36 39 40 43 45 46 48 51 53 54 57 58]
[1 2 4 7 8 11 13 14 16 19 21 22 25 26 28 31 32 35 37 38 41 42 44 47 49 50 52 55 56 59]</pre>
=={{header|Sidef}}==
<syntaxhighlight lang="ruby">func population_count(n) { n.as_bin.count('1') }
Line 4,376 ⟶ 4,573:
{{libheader|Wren-fmt}}
The first part is slightly awkward for Wren as 'native' bit-wise operations are limited to unsigned 32-bit integers and 3^21 exceeds this limit. We therefore need to switch to BigInts just before that point to process the remaining powers.
<syntaxhighlight lang="ecmascriptwren">import "./big" for BigInt
import "./fmt" for Fmt
 
var popCount = Fn.new { |n|
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