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Polynomial long division: Difference between revisions
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zx=z
nx=n copies('0 ',words(z)-words(n))
qx='' /*
Do Until words(zx)<words(n)
Parse Value div(zx,nx) With q zx
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{{out}}
<pre>(x**3-12*x**2-42)/(x-3)=(x**2-9*x-27)
Remainder: -123 </pre>
=={{header|Ruby}}==
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