Playing cards: Difference between revisions

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shuffle' g (x:xs) n ys = shuffle' g' xs (n+1) (insertAt k x ys) where
(k,g') = randomR (0,n) g</lang>
 
== Icon and Unicon ==
==={{header|Icon}}===
<lang Icon>procedure main(arglist)
 
cards := 2 # cards per hand
players := 5 # players to deal to
 
write("New deck : ", showcards(D := newcarddeck())) # create and show a new deck
write("Shuffled : ", showcards(D := shufflecards(D))) # shuffle it
 
H := list(players)
every H[1 to players] := [] # hands for each player
 
every ( c := 1 to cards ) & ( p := 1 to players ) do
put(H[p], dealcard(D)) # deal #players hands of #cards
 
every write("Player #",p := 1 to players,"'s hand : ",showcards(H[p]))
write("Remaining: ",showcards(D)) # show the rest of the deck
end
 
record card(suit,pip) #: datatype for a card suit x pip
 
procedure newcarddeck() #: return a new standard deck
local D
 
every put(D := [], card(suits(),pips()))
return D
end
 
procedure suits() #: generate suits
suspend !["H","S","D","C"]
end
 
procedure pips() #: generate pips
suspend !["2","3","4","5","6","7","8","9","10","J","Q","K","A"]
end
 
procedure shufflecards(D) #: shuffle a list of cards
every !D :=: ?D # see INL#9
return D
end
 
procedure dealcard(D) #: deal a card (from the top)
return get(D)
end
 
procedure showcards(D) #: return a string of all cards in the given list (deck/hand/etc.)
local s
every (s := "") ||:= card2string(!D) || " "
return s
end
 
procedure card2string(x) #: return a string version of a card
return x.pip || x.suit
end</lang>
Sample output:
<pre>New deck : 2H 3H 4H 5H 6H 7H 8H 9H 10H JH QH KH AH 2S 3S 4S 5S 6S 7S 8S 9S 10S JS QS KS AS 2D 3D 4D 5D 6D 7D 8D 9D 10D JD QD KD AD 2C 3C 4C 5C 6C 7C 8C 9C 10C JC QC KC AC
Shuffled : 5H 8S AC 5D 3H 9D 4S 3S 2C AD JD QH 6D 7H 4C 8H 3C KH 6S 10D 4D 8D AH 7D QS 2S QD 6H 9C KS JC 2D 10H JH 5S 2H 3D 10C 4H KC JS 8C 7S 10S KD 9S 6C 9H 7C AS QC 5C
Player #1's hand : 5H 9D
Player #2's hand : 8S 4S
Player #3's hand : AC 3S
Player #4's hand : 5D 2C
Player #5's hand : 3H AD
Remaining: JD QH 6D 7H 4C 8H 3C KH 6S 10D 4D 8D AH 7D QS 2S QD 6H 9C KS JC 2D 10H JH 5S 2H 3D 10C 4H KC JS 8C 7S 10S KD 9S 6C 9H 7C AS QC 5C</pre>
 
==={{header|Unicon}}===
This Icon solution works in Unicon.
 
=={{header|J}}==
Anonymous user