Permuted multiples: Difference between revisions
Added Swift solution
(Added Java solution) |
(Added Swift solution) |
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Line 823:
6*n = 857142
done...
</pre>
=={{header|Swift}}==
<lang swift>func getDigits(_ num: Int) -> Array<Int> {
var n = num
var digits = Array(repeating: 0, count: 10)
while true {
digits[n % 10] += 1
n /= 10
if n == 0 {
break
}
}
return digits
}
// Returns true if n, 2n, ..., 6n all have the same base 10 digits.
func sameDigits(_ n: Int) -> Bool {
let digits = getDigits(n)
for i in 2...6 {
if digits != getDigits(i * n) {
return false
}
}
return true
}
var p = 100
loop: while true {
for n in stride(from: p + 2, through: (p * 10) / 6, by: 3) {
if sameDigits(n) {
print(" n = \(n)")
for i in 2...6 {
print("\(i)n = \(i * n)")
}
break loop
}
}
p *= 10
}</lang>
{{out}}
<pre>
n = 142857
2n = 285714
3n = 428571
4n = 571428
5n = 714285
6n = 857142
</pre>
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