Partition an integer x into n primes: Difference between revisions
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V combo = [0] * m
I !find_combo(0, x, m, n, &combo)
print(‘Partitioned #5 with #2 #.: (not possible)’.format(x, m, I m > 1 {‘primes’} E
V data = [(99809, 1), (18, 2), (19, 3), (20, 4), (2017, 24),
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