Partial function application: Difference between revisions

m
mNo edit summary
Line 1,212:
println("fsf2 of s1 is $(fsf1(s2))")
println("fsf2 of s2 is $(fsf2(s2))")
{{output}}<pre>
fsf1 of s1 is [0, 2, 4, 6]
fsf2 of s1 is [0, 1, 4, 9]
fsf2 of s1 is [4, 8, 12, 16]
fsf2 of s2 is [4, 16, 36, 64]
</pre>
 
=={{header|Kotlin}}==
4,105

edits