Palindrome dates: Difference between revisions

(Added XPL0 example.)
Line 1,961:
' Write a program which calculates and shows the next 15 palindromic dates
' for those countries which express their dates in the yyyy-mm-dd format
' and for those countries which express their dates int dd-mm-yyyy format
Dim dateTest As String, Mounth As Integer, Day As Integer, Year As Integer, Pal As Integer
' the user will choose what format to use for calculating
Dim dateTest As String, Mounth As Integer, Day As Integer, Year As Integer, Pal As Integer, choice As Integer
dateTest = ""
Mounth = 0
Line 1,967 ⟶ 1,969:
Year = 0
Pal = 0
choice = 0
Print " choose date format:"
Print " press 1 for using YYYY-MM-DD format"
Print " press 2 for using DD-MM-YYYY format"
 
While choice < 1 Or choice > 2
choice = Val(InKey$)
Wend
Print " Well, you have choosen format number "; choice
Sleep 2
For Year = 2020 To 2420
dateTest = LTrim$(Str$(Year))
For Mounth = 1 To 12
If Mounth < 10 Then dateTestk$ = dateTest"0" +Else k$ = "0"
 
dateTest = dateTest + LTrim$(Str$(Mounth))
If choice = 1 Then
dateTest = dateTest + k$ + LTrim$(Str$(Mounth))
Else
dateTest = k$ + LTrim$(Str$(Mounth)) + dateTest
End If
 
 
For Day = 1 To 31
If Mounth = 2 And Day > 28 Then Exit For
If (Mounth = 4 Or Mounth = 6 Or Mounth = 9 Or Mounth = 11) And Day > 30 Then Exit For
If Day < 10 Then dateTestk$ = dateTest"0" +Else k$ = "0"
dateTestIf =choice dateTest= +1 LTrim$(Str$(Day))Then
dateTest = dateTest + k$ + LTrim$(Str$(Day))
Else
dateTest = k$ + LTrim$(Str$(Day)) + dateTest
End If
'Print dateTest: Sleep
For Pal = 1 To 4
Line 1,982 ⟶ 2,005:
Next
If Pal = 5 Then Print dateTest
dateTestIf choice = Left$(dateTest,1 6)Then
dateTest = Left$(dateTest, 6)
Else
dateTest = Right$(dateTest, 6)
End If
Next
dateTestIf choice = Left$(dateTest,1 4)Then
dateTest = Left$(dateTest, 4)
Else
dateTest = Right$(dateTest, 4)
End If
Next
dateTest = ""
Next
 
 
</lang>