Order two numerical lists: Difference between revisions

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     [2015,5] is not lexically prior to
     [-7.0710678118654755,2500.0]
+</pre>
+=={{header|Kotlin}}==
+<lang scala>// version 1.0.6
+operator fun <T> List<T>.compareTo(other: List<T>): Int
+    where T: Comparable<T>, T: Number {
+    for (i in 0 until this.size) {
+        if (other.size == i) return 1
+        when {
+            this[i] < other[i] -> return -1
+            this[i] > other[i] -> return 1
+        }
+    }
+    return if (this.size == other.size) 0 else -1
+}
+fun main(args: Array<String>) {
+    val list1 = listOf(1, 2, 3, 4, 5)
+    val list2 = listOf(1, 2, 1, 5, 2, 2)
+    val list3 = listOf(1, 2, 1, 5, 2)
+    val list4 = listOf(1, 2, 1, 5, 2)
+    val list5 = listOf(1, 2, 1, 3, 2)
+    val list6 = listOf(1, 2, 0, 4, 4, 0, 0, 0)
+    val list7 = listOf(1, 2, 0, 4, 4, 1, 0, 0)
+    println("list1 : $list1")
+    println("list2 : $list2")
+    println("list3 : $list3")
+    println("list4 : $list4")
+    println("list5 : $list5")
+    println("list6 : $list6")
+    println("list7 : $list7")
+    println()
+    println("list1 > list2 = ${list1 > list2}")
+    println("list2 > list3 = ${list2 > list3}")
+    println("list3 > list4 = ${list3 > list4}")
+    println("list4 > list5 = ${list4 > list5}")
+    println("list5 > list6 = ${list5 > list6}")
+    println("list6 > list7 = ${list6 > list7}")
+}</lang>
+{{out}}
+<pre>
+list1 : [1, 2, 3, 4, 5]
+list2 : [1, 2, 1, 5, 2, 2]
+list3 : [1, 2, 1, 5, 2]
+list4 : [1, 2, 1, 5, 2]
+list5 : [1, 2, 1, 3, 2]
+list6 : [1, 2, 0, 4, 4, 0, 0, 0]
+list7 : [1, 2, 0, 4, 4, 1, 0, 0]
+list1 > list2 = true
+list2 > list3 = true
+list3 > list4 = false
+list4 > list5 = true
+list5 > list6 = true
+list6 > list7 = false
 </pre>