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Order two numerical lists: Difference between revisions
added a few languages' built-in support
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(added a few languages' built-in support) |
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Line 18:
return string(a) < string(b)
}</lang>
=={{header|Haskell}}==
The built-in comparison operators already do this:
<lang haskell>Prelude> [1,2,1,3,2] < [1,2,0,4,4,0,0,0]
False</lang>
=={{header|Java}}==
Line 57 ⟶ 62:
}</lang>
=={{header|OCaml}}==
The built-in comparison operators already do this:
<lang ocaml># [1;2;1;3;2] < [1;2;0;4;4;0;0;0];;
- : bool = false</lang>
The function that achieves the task:
Line 111 ⟶ 120:
return a[0] < b[0];
}</lang>
=={{header|Python}}==
The built-in comparison operators already do this:
<lang python>>>> [1,2,1,3,2] < [1,2,0,4,4,0,0,0]
False</lang>
=={{header|Ruby}}==
The built-in <code><=></code> operator already does this:
<lang ruby>>> ([1,2,1,3,2] <=> [1,2,0,4,4,0,0,0]) < 0
=> false</lang>
=={{header|Tcl}}==
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