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Order disjoint list items: Difference between revisions
→{{header|Haskell}}: simplify cases
(→{{header|Haskell}}: minor improvement) |
(→{{header|Haskell}}: simplify cases) |
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Line 696:
ks = zip ms [(0::Int)..]
ls = zip ns.sort.snd.foldl go (sort ns,[]).sort $ ks
yu
yu
go (
go ts
task ls@[ms,ns] = do
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