Operator precedence: Difference between revisions

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=={{header|Kotlin}}==
=={{header|Kotlin}}==
This is well-documented [https://kotlinlang.org/docs/reference/grammar.html on the Kotlin language website].
This is well-documented [https://kotlinlang.org/docs/reference/grammar.html on the Kotlin language website].

=={{header|Lambdatalk}}==
<lang Scheme>
As with Common Lisp and Scheme, Lambdatalk uses s-expressions so there is no need for operator precedence.
Such an expression "1+2*3+4" is written {+ 1 {* 2 3} 4}
</lang>


=={{header|LIL}}==
=={{header|LIL}}==