Numeric error propagation: Difference between revisions
Content deleted Content added
Line 567:
return (numeric(a)^numeric(b)) |
num(f := a.val^numeric(b), abs(f*b*(a.err/a.val)))
end</lang>
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Line 567:
return (numeric(a)^numeric(b)) |
num(f := a.val^numeric(b), abs(f*b*(a.err/a.val)))
end</lang>
|