Numbers with prime digits whose sum is 13: Difference between revisions

→‎AWK: →‎bc: →‎OCaml: →‎Python: some simplification
(→‎bc: add)
(→‎AWK: →‎bc: →‎OCaml: →‎Python: some simplification)
Line 83:
BYTE ARRAY digits(MAXDIG)
BYTE count,pos
 
count=1 pos=0
Init(count)
Line 211:
=={{header|Arturo}}==
<syntaxhighlight lang="rebol">pDigits: [2 3 5 7]
 
lst: map pDigits 'd -> @[d]
result: new []
Line 286:
===Generate digit combinations directly===
<syntaxhighlight lang="awk">BEGIN {
split("2o 3= 5 7", digits)1
src[i = 0o++] = 13
odo = 2{
res r = ""src[++i]
while (i != o) {n = src[++i]
rfor (p = src[i2; p != 9; p += p % 2 +] 1) {
n if (p >= src[i++]r) {
for (d = 1; d != 5 && if (p == digits[d]r) <res = r;res ++d)" {" n p
if (p == r) {break
res = res " " n p
} else {
src[o++] = r - p
src[o++] = n p
}
ressrc[++o] = res " "r n- p
}src[++o] else= {n p
}
} while (i != o)
print substr(res, 2)
}</syntaxhighlight>
}
</syntaxhighlight>
{{out}}
<pre>337 355 373 535 553 733 2227 2272 2335 2353 2533 2722 3235 3253 3325 3352 3523 3532 5233 5323 5332 7222 22225 22252 22333 22522 23233 23323 23332 25222 32233 32323 32332 33223 33232 33322 52222 222223 222232 222322 223222 232222 322222</pre>
Line 316 ⟶ 313:
for (p = 2; p != 9; p += p % 2 + 1) {
if (p >= r) {
if (p == r) n * 10 + p
break
}
q[o++] = r - p
q[o++] = (n * 10 + p) * 10
}
}</syntaxhighlight>
Line 1,196 ⟶ 1,193:
reduce .[] as $i ([]; .[$i] += 1);
(length|factorial) / (histogram|product_of_factorials);
 
def number_of_interesting_numbers($total):
def digits: [2, 3, 5, 7];
Line 1,420 ⟶ 1,417:
| (n, r) :: cs' as cs ->
match ds with
| d :: ds' when d < r -> next ds' (((n * 10 + d) * 10, r - d) :: ns) cs
| d :: ds' when d = r -> n * 10 + d :: next digits ns cs'
| _ -> next digits ns cs'
in next digits [] [0, 13]
Line 1,920 ⟶ 1,917:
<span style="color: #008080;">return</span> <span style="color: #000000;">res</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
 
<span style="color: #004080;">sequence</span> <span style="color: #000000;">r</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">sort</span><span style="color: #0000FF;">(</span><span style="color: #000000;">unlucky</span><span style="color: #0000FF;">({</span><span style="color: #000000;">2</span><span style="color: #0000FF;">,</span><span style="color: #000000;">3</span><span style="color: #0000FF;">,</span><span style="color: #000000;">5</span><span style="color: #0000FF;">,</span><span style="color: #000000;">7</span><span style="color: #0000FF;">},</span><span style="color: #000000;">13</span><span style="color: #0000FF;">))</span>
<span style="color: #7060A8;">puts</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #7060A8;">join_by</span><span style="color: #0000FF;">(</span><span style="color: #000000;">r</span><span style="color: #0000FF;">,</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #000000;">11</span><span style="color: #0000FF;">,</span><span style="color: #008000;">" "</span><span style="color: #0000FF;">))</span>
Line 1,951 ⟶ 1,948:
<span style="color: #008080;">return</span> <span style="color: #000000;">res</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
 
<span style="color: #004080;">sequence</span> <span style="color: #000000;">r</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">unlucky</span><span style="color: #0000FF;">()</span>
<span style="color: #000000;">r</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">apply</span><span style="color: #0000FF;">(</span><span style="color: #004600;">true</span><span style="color: #0000FF;">,</span><span style="color: #7060A8;">sprintf</span><span style="color: #0000FF;">,{{</span><span style="color: #008000;">"%6d"</span><span style="color: #0000FF;">},</span><span style="color: #000000;">r</span><span style="color: #0000FF;">})</span>
Line 2,002 ⟶ 1,999:
for d in 2, 3, 5, 7:
if d >= r:
if d == r: yield n * 10 + d
break
q.append((r - d, (n * 10 + d) * 10))
 
print(*prime_digits_sum(13))</syntaxhighlight>
559

edits