Numbers k such that the last letter of k is the same as the first letter of k+1: Difference between revisions

(Added Algol 68)
Line 76:
INT next to show := 1 000;
INT count := 0;
print( ( "The first 50 numbers:", newline ) );
FOR n WHILE count < 1 000 000 DO
INT k = n - 1;
Line 97 ⟶ 98:
FI
FI;
prev end := IF INT n99 = n MOD 1 000 = 0100;
prev end THEN:= IF n MOD 1n99 000 000 => 0
THEN e99[ n99 THEN "n"]
ELIF n MOD 1 000 ELSE000 "d"= 0
THEN FI"n"
ELSE INT n99 = n MOD 100;"d"
IF n99 = 0
THEN "d"
ELSE e99[ n99 ]
FI
FI
OD
Line 113 ⟶ 110:
{{out}}
<pre>
The first 50 numbers:
0 18 28 38 79 81 83 85 97 102
122 132 142 152 162 172 182 192 208 228
3,048

edits