Multiplicative order: Difference between revisions

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=={{header|PARI/GP}}==
<lang parigp>znorder(Mod(a,n))</lang>
=={{header|Perl 6}}==
<lang perl6>my @primes := 2, grep *.is-prime, (3,5,7...*);
 
sub factor($a is copy) {
gather {
for @primes -> $p {
my $j = 0;
while $a %% $p {
$a div= $p;
$j++;
}
take $p => $j if $j > 0;
last if $a < $p * $p;
}
take $a => 1 if $a > 1;
}
}
sub mo-prime($a, $p, $e) {
my $m = $p ** $e;
my $t = ($p - 1) * ($p ** ($e - 1)); # = Phi($p**$e) where $p prime
my @qs = 1;
for factor($t) -> $f {
@qs = @qs.map(-> $q { (0..$f.value).map(-> $j { $q * $f.key ** $j }) });
}
@qs.sort();
@qs.first(-> $q { expmod( $a, $q, $m ) == 1});
}
sub mo($a, $m) {
$a gcd $m == 1 || die "$a and $m are not relatively prime";
[lcm] 1, factor($m).map(-> $r { mo-prime($a, $r.key, $r.value) });
}
sub MAIN("test") {
use Test;
for (10, 21, 25, 150, 1231, 123141, 34131) -> $n {
# say factor($n).perl;
# say factor($n).map(-> $pair { $pair.key ** $pair.value }).perl;
is ([*] factor($n).map(-> $pair { $pair.key ** $pair.value })), $n, "$n factors correctly";
}
is mo(37, 1000), 100, 'mo(37,1000) == 100';
my $b = 10**20-1;
is mo(2, $b), 3748806900, 'mo(2,10**20-1) == 3748806900';
is mo(17, $b), 1499522760, 'mo(17,10**20-1) == 1499522760';
$b = 100001;
is mo(54, $b), 9090, 'mo(54,100001) == 9090';
}</lang>
{{out}}
<pre>ok 1 - 10 factors correctly
ok 2 - 21 factors correctly
ok 3 - 25 factors correctly
ok 4 - 150 factors correctly
ok 5 - 1231 factors correctly
ok 6 - 123141 factors correctly
ok 7 - 34131 factors correctly
ok 8 - mo(37,1000) == 100
ok 9 - mo(2,10**20-1) == 3748806900
ok 10 - mo(17,10**20-1) == 1499522760
ok 11 - mo(54,100001) == 9090</pre>
 
=={{header|Python}}==
Anonymous user