Monty Hall problem: Difference between revisions

Content added Content deleted
(Add Seed7 example)
(→‎{{header|C sharp|C#}}: simplify program)
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<lang csharp>using System;
<lang csharp>using System;


class Program
namespace MontyHallProblem
{
{
static void Main(string[] args)
class Program
{
{
static void Main(string[] args)
int switchWins = 0;
{
int stayWins = 0;
int switchWins = 0;
int stayWins = 0;


Random gen = new Random();
Random gen = new Random();
for(int plays = 0; plays < 1000000; plays++ )
for(int plays = 0; plays < 1000000; plays++ )
{
{
int[] doors = {0,0,0};//0 is a goat, 1 is a car
int[] doors = {0,0,0};//0 is a goat, 1 is a car


var winner = gen.Next(3);
var winner = gen.Next(3);
doors[winner] = 1; //put a winner in a random door
doors[winner] = 1; //put a winner in a random door
int choice = gen.Next(3); //pick a door, any door
int choice = gen.Next(3); //pick a door, any door
int shown; //the shown door
int shown; //the shown door
do
do
{
{
shown = gen.Next(3);
shown = gen.Next(3);
}
}
while(doors[shown] == 1 || shown == choice); //don't show the winner or the choice
while (doors[shown] == 1 || shown == choice); //don't show the winner or the choice
stayWins += doors[choice];//if you won by staying, count it
stayWins += doors[choice]; //if you won by staying, count it
//the switched (last remaining) door is (3 - choice - shown), because 0+1+2=3
//the switched (last remaining) door is (3 - choice - shown), because 0+1+2=3
switchWins += doors[3 - choice - shown];
switchWins += doors[3 - choice - shown];
}
}


System.Console.Out.Write("Switching wins " + switchWins + " times.");
Console.Out.Write("Switching wins " + switchWins + " times.");
System.Console.Out.Write("Staying wins " + stayWins + " times.");
Console.Out.Write("Staying wins " + stayWins + " times.");
}
}
}
}</lang>
}</lang>