Monty Hall problem: Difference between revisions
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<lang dyalect>var switchWins = 0 |
<lang dyalect>var switchWins = 0 |
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var stayWins = 0 |
var stayWins = 0 |
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for plays in 0..1000000 { |
for plays in 0..1000000 { |
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var doors = [0 ,0, 0] |
var doors = [0 ,0, 0] |
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var winner = rnd(3) |
var winner = rnd(max: 3) |
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doors[winner] = 1 |
doors[winner] = 1 |
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var choice = rnd(3) |
var choice = rnd(max: 3) |
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var shown = rnd(3) |
var shown = rnd(max: 3) |
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while doors[shown] == 1 || shown == choice { |
while doors[shown] == 1 || shown == choice { |
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shown = rnd(3) |
shown = rnd(max: 3) |
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} |
} |
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stayWins += doors[choice] |
stayWins += doors[choice] |
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switchWins += doors[3 - choice - shown] |
switchWins += doors[3 - choice - shown] |
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} |
} |
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print("Staying wins \(stayWins) times.") |
print("Staying wins \(stayWins) times.") |
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print("Switching wins \(switchWins) times.")</lang> |
print("Switching wins \(switchWins) times.")</lang> |
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{{out}} |
{{out}} |
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<pre>Staying wins |
<pre>Staying wins 286889 times. |
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Switching wins |
Switching wins 713112 times.</pre> |
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=={{header|Eiffel}}== |
=={{header|Eiffel}}== |
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