Modular arithmetic: Difference between revisions
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<pre>x ^ 100 + x + 1 for ModInt(10, 13) is ModInt(1, 13)</pre>
=={{header|Mathematica}}/{{header|Wolfram Language}}==
The best way to do it is probably to use the finite fields package.
<lang Mathematica><< FiniteFields`
x^100 + x + 1 /. x -> GF[13]@{10}</lang>
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{1}<sub>13</sub>
=={{header|Nim}}==
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