Modular arithmetic: Difference between revisions
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<pre>x ^ 100 + x + 1 for ModInt(10, 13) is ModInt(1, 13)</pre> |
<pre>x ^ 100 + x + 1 for ModInt(10, 13) is ModInt(1, 13)</pre> |
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=={{header|Mathematica}}/{{header|Wolfram Language}}== |
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The best way to do it is probably to use the finite fields package. |
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<lang Mathematica><< FiniteFields` |
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x^100 + x + 1 /. x -> GF[13]@{10}</lang> |
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{1}<sub>13</sub> |
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=={{header|Nim}}== |
=={{header|Nim}}== |
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