Minimum multiple of m where digital sum equals m: Difference between revisions
Minimum multiple of m where digital sum equals m (view source)
Revision as of 23:35, 2 July 2024
, 4 days ago→{{header|Quackery}}: simplified code
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drop ] is digitsum ( n --> n )
[]
40 times
[
[ dup dup index * ▼
[ dup dup
digitsum =
1+
drop echo</syntaxhighlight>
{{out}}
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