Mertens function: Difference between revisions
m
→{{header|EasyLang}}
m (→{{header|Wren}}: Minor tidy) |
|||
| (One intermediate revision by the same user not shown) | |||
Line 1,748:
M(n) is zero 92 times for 1 <= n <= 1000.
M(n) crosses zero 59 times for 1 <= n <= 1000.</pre>
=={{header|EasyLang}}==
{{trans|FutureBasic}}
<syntaxhighlight>
len mertens[] 1000
mertens[1] = 1
for n = 2 to 1000
mertens[n] = 1
for k = 2 to n
mertens[n] -= mertens[n div k]
.
.
print "First 99 Mertens numbers:"
write " "
numfmt 0 2
for n = 1 to 99
write mertens[n] & " "
if n mod 10 = 9
print ""
.
.
for n = 1 to 1000
if mertens[n] = 0
zeros += 1
if mertens[n - 1] <> 0
crosses += 1
.
.
.
print ""
print "In the first 1000 terms of the Mertens sequence there are:"
print zeros & " zeros"
print crosses & " zero crosses"
</syntaxhighlight>
{{out}}
<pre>
First 99 Mertens numbers:
1 0 -1 -1 -2 -1 -2 -2 -2
-1 -2 -2 -3 -2 -1 -1 -2 -2 -3
-3 -2 -1 -2 -2 -2 -1 -1 -1 -2
-3 -4 -4 -3 -2 -1 -1 -2 -1 0
0 -1 -2 -3 -3 -3 -2 -3 -3 -3
-3 -2 -2 -3 -3 -2 -2 -1 0 -1
-1 -2 -1 -1 -1 0 -1 -2 -2 -1
-2 -3 -3 -4 -3 -3 -3 -2 -3 -4
-4 -4 -3 -4 -4 -3 -2 -1 -1 -2
-2 -1 -1 0 1 2 2 1 1 1
In the first 1000 terms of the Mertens sequence there are:
92 zeros
59 zero crosses
</pre>
=={{header|F_Sharp|F#}}==
| |||