Matrix transposition: Difference between revisions

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import java.util.Arrays;
public class Transpose{
public static void main(String[] args){
double[][] m = {{1, 1, 1, 1},
{2, 4, 8, 16},
{3, 9, 27, 81},
{4, 16, 64, 256},
{5, 25, 125, 625}};
double[][] ans = new double[m[0].length][m.length];
for(int rows = 0; rows < m.length; rows++){
for(int cols = 0; cols < m[0].length; cols++){
ans[cols][rows] = m[rows][cols];
}
}
}
}
for(double[] i:ans){//2D arrays are arrays of arrays
System.out.println(Arrays.toString(i));
}
}
}
}
 
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1.00000 8.00000 27.00000 64.00000 125.00000
1.00000 16.00000 81.00000 256.00000 625.00000
 
=={{header|Pop11}}==
 
<pre>
define transpose(m) -> res;
lvars bl = boundslist(m);
if length(bl) /= 4 then
throw([need_2d_array ^a])
endif;
lvars i, i0 = bl(1), i1 = bl(2);
lvars j, j0 = bl(3), j1 = bl(4);
newarray([^j0 ^j1 ^i0 ^i1], 0) -> res;
for i from i0 to i1 do
for j from j0 to j1 do
m(i, j) -> res(j, i);
endfor;
endfor;
enddefine;
</pre>
 
=={{header|Python}}==
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=={{header|TI-83 BASIC}}==
Assuming the original matrix is in <tt>[A]</tt>, place its transpose in <tt>[B]</tt>:
[A]<sup>T</sup>→->[B]
The <sup>T</sup> operator can be found in the matrix math menu.
Retrieved from "https://rosettacode.org/wiki/Matrix_transposition"