Matrix multiplication: Difference between revisions

Updated D entry
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(Updated D entry)
Line 1,015:
immutable Bt = B[0].length.iota.map!(i=> B.transversal(i).array)
.array;
return A.map!((immutable T[]in a) => Bt.map!(b => a.dotProduct(b)).array).array;
.array).array;
}