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Loops/With multiple ranges: Difference between revisions
→{{header|C sharp}}
Line 854:
sum = 348,173
prod = -793,618,560</pre>
=={{header|C++}}==
{{works with|C++11}}
C++ doesn't natively support multiple ranges, but we can simulate that using a list and then iterating over the values in that list.
<lang cpp>#include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}</lang>
{{out}}
<pre>sum = 348173
prod = -793618560</pre>
=={{header|Common Lisp}}==
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