Loops/While

Loops/While
You are encouraged to solve this task according to the task description, using any language you may know.

Start an integer value at 1024. Loop while it is greater than 0. Print the value (with a newline) and divide it by two each time through the loop.

ActionScript

<lang actionscript> var i:int = 1024; while (i > 0) {

   trace(i);
   i /= 2;

} </lang>

Ada

<lang ada> declare

  I : Integer := 1024;

begin

  while I > 0 loop
     Put_Line(Integer'Image(I));
     I := I / 2;
  end loop;

end; </lang>

ALGOL 68

Works with: ALGOL 68 version Standard - no extensions to language used

Works with: ALGOL 68G version Any - tested with release mk15-0.8b.fc9.i386

Works with: ELLA ALGOL 68 version Any (with appropriate job cards) - tested with release 1.8.8d.fc9.i386

INT i := 1024;
WHILE i > 0 DO
   print((i));
   i := i OVER 2
OD

Output:

      +1024       +512       +256       +128        +64        +32        +16         +8         +4         +2         +1

AWK

<lang awk>BEGIN {

 v = 1024
 while(v > 0) {
   print v
   v = int(v/2)
 }

}</lang>

BASIC

Works with: QuickBasic version 4.5

<lang qbasic>i = 1024 while i > 0

  print i
  i = i / 2

wend</lang>

Befunge

84*:*>   :v
     ^/2.:_@

C

<lang c>int i = 1024; while(i > 0) {

 printf("%d\n", i);
 i /= 2;

}</lang> In for loop fashion: <lang c>int i; for(i = 1024;i > 0; i/=2){

  printf("%d\n", i);

}</lang>

C++

<lang cpp>int i = 1024; while(i > 0) {

 std::cout << i << std::endl;
 i /= 2;

}</lang> Alternatively, it can be done with for: <lang cpp> for (int i = 1024; i>0; i /= 2)

 std::cout << i << std::endl;

</lang> Indeed, in C++, <lang cpp> for (init; cond; update)

 statement;

</lang> is equivalent to <lang cpp> {

 init;
 while (cond)
 {
   statement;
   update;
 }

} </lang>

C#

<lang c>int i = 1024; while(i > 0){

  System.Console.WriteLine(i);
  i /= 2;

}</lang>

ColdFusion

Remove the leading space from the line break tag.

With tags:

<cfset i = 1024 />
<cfloop condition="i GT 0">
  #i#< br />
  <cfset i /= 2 />
</cfloop>

With script:

<cfscript>
  i = 1024;
  while( i > 0 )
  {
    writeOutput( i + "< br/ >" );
  }
</cfscript>

Common Lisp

<lang lisp>(setq i 1024) (loop while (> i 0) do

 (print i)
 (setq i (floor i 2)))</lang>

D

<lang d>import std.stdio;

int i = 1024; void main() {

   while(i > 0) {
       writefln("%s", i);
       i >>= 1;
   }

}</lang>

Forth

<lang forth>

: halving ( n -- )
  begin  dup 0 >
  while  cr dup .  2/
  repeat drop ;
1024 halving

</lang>

Factor

 1024 [ dup 0 > ] [ dup . 2 /i ] [ drop ] while

Fortran

Works with: Fortran version 90 and later

<lang fortran>

INTEGER :: i = 1024
DO WHILE (i > 0)
  WRITE(*,*) i
  i = i / 2
END DO

</lang>

Haskell

<lang haskell>

import Control.Monad
main = loop 1024      
  where loop n = when (n > 0)
                      (do print n
                          loop (n `div` 2))

</lang>

Icon

<lang icon>

procedure main()
   local i
   i := 1024
   while write(0 < (i := i / 2))
end

</lang>

J

J is array-oriented, so there is very little need for loops. For example, one could satisfy this task this way:

<lang j>

  ,. <.@-:^:*^:a: 1024

</lang>

J does support loops for those times they can't be avoided (just like many languages support gotos for those time they can't be avoided).

<lang j>

  3 : 0 ] 1024

       while. 0 < y do.
            y 1!:2 ] 2
            y =. <. -: y 
       end.

      i. 0 0
  )

</lang>

Though it's rare to see J code like this.

Java

<lang java5>int i = 1024; while(i > 0){

  System.out.println(i);
  i >>= 1; //also acceptable: i /= 2;

}</lang> With a for loop: <lang java5>for(int i = 1024; i > 0;i /= 2 /*or i>>= 1*/){

  System.out.println(i);

}</lang>

JavaScript

<lang javascript>var n = 1024; while (n>0) {

print(n);
n/=2;

}</lang>

Logo

make "n 1024
while [:n > 0] [print :n  make "n :n / 2]

MAXScript

a = 1024
while a > 0 do
(
    print a
    a /= 2
)

Make

NEXT=`expr $* / 2`
MAX=10

all: $(MAX)-n;

0-n:;

%-n: %-echo
       @-make -f while.mk $(NEXT)-n MAX=$(MAX)

%-echo:
       @echo $*

Invoking it

|make -f while.mk MAX=1024

Modula-3

The usual module code and imports are omitted. <lang modula3>PROCEDURE DivBy2() =

 VAR i: INTEGER := 1024;
 BEGIN
   WHILE i > 0 DO
     IO.PutInt(i);
     IO.Put("\n");
     i := i DIV 2;
   END;
 END DivBy2;</lang>

Oberon-2

The usual module code and imports are ommited. <lang oberon2>PROCEDURE DivBy2*();

 VAR i: INTEGER;

BEGIN

 i := 1024;
 WHILE i > 0 DO
   Out.Int(i,0);
   Out.Ln;
   i := i DIV 2;
 END;

END DivBy2;</lang>

OCaml

<lang ocaml>let n = ref 1024;; while !n > 0 do

 Printf.printf "%d\n" !n;
 n := !n / 2

done;;</lang>

But it is more common to write it in a tail-recursive functional style: <lang ocaml>let rec loop n =

 if n > 0 then begin
   Printf.printf "%d\n" n;
   loop (n / 2)
 end

in loop 1024</lang>

Pascal

<lang pascal> program divby2(output);

var

 i: integer;

begin

 i := 1024;
 while i > 0 do
   begin
     writeln(i);
     i := i div 2
   end

end. </lang>

Perl

<lang perl>$n = 1024; while ($n > 0) {

   print "$n\n";
   $n >>= 1; # also acceptable: use integer; $n /= 2;

}</lang>

PHP

<lang php>$i = 1024; while ($i > 0) {

  echo "$i\n";
  $i >>= 1;

}</lang>

Pop11

lvars i = 1024;
while i > 0 do
    printf(i, '%p\n');
    i div 2 -> i;
endwhile;

Prolog

<lang prolog>while(0) :- !. while(X) :- write(X), nl, X1 is X // 2, while(X1).</lang>

Python

<lang python>n = 1024 while n > 0:

   print n
   n //= 2</lang>

Ruby

<lang ruby>i = 1024 while i > 0 do

  puts i
  i /= 2

end</lang>

Scheme

<lang scheme> (do ((n 1024 (quotient n 2)))

   ((<= n 0))
   (display n)
   (newline))</lang>

Standard ML

<lang sml>val n = ref 1024; while !n > 0 do (

 print (Int.toString (!n) ^ "\n");
 n := !n div 2

)</lang>

But it is more common to write it in a tail-recursive functional style: <lang sml>let

 fun loop n =
   if n > 0 then (
     print (Int.toString n ^ "\n");
     loop (n div 2)
   ) else ()

in

 loop 1024

end</lang>

Tcl

<lang tcl>set i 1024 while {$i > 0} {

   puts $i
   set i [expr {$i / 2}]

}</lang>

UnixPipes

(echo 1024>p.res;tail -f p.res) | while read a ; do
   test $a -gt 0 && (expr $a / 2  >> p.res ; echo $a) || exit 0
done

V

1024 [0 >] [
   dup puts
   2 / >int
] while

Visual Basic .NET

       Dim x = 1024
       Do
           Console.WriteLine(x)
           x = x \ 2
       Loop While x > 0