Loops/Break: Difference between revisions
< Loops
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m (→{{header|BASIC}}: Added note about EXIT FOR) |
(Forth) |
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print b |
print b |
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loop</lang> |
loop</lang> |
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=={{header|Forth}}== |
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<lang forth>include random.fs |
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: main |
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begin 20 random dup . 10 <> |
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while 20 random . |
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repeat ; |
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\ use LEAVE to break out of a counted loop |
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: main |
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100 0 do |
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i random dup . |
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10 = if leave then |
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i random . |
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loop ; |
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</lang> |
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=={{header|Java}}== |
=={{header|Java}}== |
Revision as of 22:48, 5 June 2009
![Task](http://static.miraheze.org/rosettacodewiki/thumb/b/ba/Rcode-button-task-crushed.png/64px-Rcode-button-task-crushed.png)
You are encouraged to solve this task according to the task description, using any language you may know.
Show a while loop which prints two random numbers (newly generated each loop) from 0 to 19 (inclusive). If the first number is 10, print it, stop the loop, and do not generate the second. Otherwise, loop forever.
BASIC
<lang qbasic>do
a = int(rnd * 20) print a if a = 10 then exit loop 'EXIT FOR works the same inside FOR loops b = int(rnd * 20) print b
loop</lang>
Forth
<lang forth>include random.fs
- main
begin 20 random dup . 10 <> while 20 random . repeat ;
\ use LEAVE to break out of a counted loop
- main
100 0 do i random dup . 10 = if leave then i random . loop ;
</lang>
Java
<lang java>while(true){
int a = (int)(Math.random()*20); System.out.println(a); if(a == 10) break; int b = (int)(Math.random()*20); System.out.println(b);
}</lang>