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Longest common prefix: Difference between revisions
Rather than creating a new string, update its length.
(Rather than creating a new string, update its length.) |
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Line 2,230:
result = list[0]
for i in 1..list.high:
var
for j, c in result:
if j >= list[i].len or list[i][j] != c:
break
result
proc test(list: varargs[string]) =
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