Number names

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ALGOL 68

PROC number words =

``` (
INT n
) STRING :
# returns a string representation of n in words. Currently
deals with anything from 0 to 999 999 999. #
BEGIN
[] STRING digits =
[] STRING (
"zero",
"one",
"two",
"three",
"four",
"five",
"six",
"seven",
"eight",
"nine"
)[@0];
[] STRING teens =
[] STRING (
"ten",
"eleven",
"twelve",
"thirteen",
"fourteen",
"fifteen",
"sixteen",
"seventeen",
"eighteen",
"nineteen"
)[@0];
[] STRING (
"twenty",
"thirty",
"forty",
"fifty",
"sixty",
"seventy",
"eighty",
"ninety"
)[@2];
```
```       PROC three digits =
(
INT n
) STRING :
# does the conversion for n from 0 to 999. #
BEGIN
INT tens = n MOD 100 OVER 10;
INT units = n MOD 10;
IF n >= 100 THEN
digits[n OVER 100]
+
" "
+
"hundred"
+
IF n MOD 100 /= 0 THEN
" and "
ELSE
""
FI
ELSE
""
FI
+
IF tens /= 0 THEN
IF tens = 1 THEN
teens[units]
ELSE
+
IF units /= 0 THEN
"-"
ELSE
""
FI
FI
FI
+
IF units /= 0 AND tens /= 1 OR n = 0 THEN
digits[units]
ELSE
""
FI
END;
INT n3 = n OVER 1 000 000;
INT n2 = n MOD 1 000 000 OVER 1000;
INT n1 = n MOD 1000;
IF n3 /= 0 THEN
three digits(n3) + " million"
ELSE
""
FI
+
IF n3 /= 0 AND (n2 /= 0 OR n1 >= 100) THEN
", "
ELSE
""
FI
+
IF n2 /= 0 THEN
three digits(n2) + " thousand"
ELSE
""
FI
+
IF (n3 /= 0 OR n2 /= 0) AND n1 > 0 AND n1 < 100 THEN
" and "
ELIF n2 /= 0 AND n1 /= 0 THEN
", "
ELSE
""
FI
+
IF n1 /= 0 OR n = 0 THEN
three digits(n1)
ELSE
""
FI
END;
```

DO # until user hits EOF #

```   on logical file end(standin, (REF FILE f) BOOL : GOTO finish);
on value error(standin, (REF FILE f) BOOL : GOTO finish);
INT n;
print("n? ");