Last Friday of each month: Difference between revisions

Added Algol W
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(Added Algol W)
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2012-11-30
2012-12-28</pre>
 
=={{header|ALGOL W}}==
Basically the same as the "Find the Last Sunday Of Each Month" task solution, uses the Day_of_week and isLeapYear procedures from the the day-of-the-week and leap-year tasks (included here for convenience).
<lang algolw>begin % find the last Friday in each month of a year %
% returns true if year is a leap year, false otherwise %
% assumes year is in the Gregorian Calendar %
logical procedure isLeapYear ( integer value year ) ;
year rem 400 = 0 or ( year rem 4 = 0 and year rem 100 not = 0 );
% returns the day of the week of the specified date (d/m/y) %
% Sunday = 1, Friday = 6, Saturday = 0 %
integer procedure Day_of_week ( integer value d, m, y );
begin
integer j, k, mm, yy;
mm := m;
yy := y;
if mm <= 2 then begin
mm := mm + 12;
yy := yy - 1;
end if_m_le_2;
j := yy div 100;
k := yy rem 100;
(d + ( ( mm + 1 ) * 26 ) div 10 + k + k div 4 + j div 4 + 5 * j ) rem 7
end Day_of_week;
% sets the elements of last to the day of the last Friday %
% of each month in year %
procedure lastFridays ( integer value year
; integer array last ( * )
) ;
begin
integer array lastDays ( 1 :: 12 );
integer m;
% set ld to the day number od the last day of each %
% month in year %
m := 1;
for ld := 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 do begin
lastDays( m ) := ld;
m := m + 1
end for_ld ;
if isLeapYear( year ) then lastDays( 2 ) := 29;
% for each month, determine the day number of the %
% last Friday %
for mPos := 1 until 12 do begin
integer dow;
dow := Day_of_week( lastDays( mPos ), mPos, year );
% dow = 1 Sun, 2 Mon, ... , 6 Fri, 0 Sat %
% change to 2 Sun, 3 Mon, ... , 0 Fri, 1 Sat %
dow := ( dow + 1 ) rem 7;
% offset the last day to the last Friday %
last( mPos ) := lastDays( mPos ) - dow
end for_mPos
end lastFridays ;
begin
% test the lastFridays procedure %
integer array last ( 1 :: 12 );
integer year;
year := 2020;
lastFridays( year, last );
i_w := 1; s_w := 0; % output formatting %
for mPos := 1 until 12 do write( year, if mPos < 10 then "-0" else "-1", mPos rem 10, "-", last( mPos ) )
end
end.</lang>
{{out}}
<pre>
2020-01-31
2020-02-28
2020-03-27
2020-04-24
2020-05-29
2020-06-26
2020-07-31
2020-08-28
2020-09-25
2020-10-30
2020-11-27
2020-12-25
</pre>
 
=={{header|AppleScript}}==
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