Last Friday of each month: Difference between revisions
Content added Content deleted
m (→{{header|Perl 6}}: remove final $_) |
(→{{header|Perl 6}}: added alternative solution) |
||
Line 502: | Line 502: | ||
2038-11-26 |
2038-11-26 |
||
2038-12-31</pre> |
2038-12-31</pre> |
||
A solution without a result array to store things in: |
|||
<lang perl6>sub MAIN (Int $year = Date.today.year) { |
|||
say ~.value.reverse.first: *.day-of-week == 5 |
|||
for (Date.new("$year-01-01") .. Date.new("$year-12-31")).classify: *.month; |
|||
}</lang> |
|||
Here, <code>.classify</code> sorts the dates into one bin per month (but preserves the order in each bin). We then take the list inside each bin (<code>.value</code>) and find the last (<code>.reverse.first</code>) date which is a Friday. |
|||
=={{header|PHP}}== |
=={{header|PHP}}== |