Last Friday of each month: Difference between revisions

Added Easylang
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(Added Easylang)
 
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2012-12-28
</pre>
 
=={{header|BBC BASIC}}==
{{works with|BBC BASIC for Windows}}
<syntaxhighlight lang="bbcbasic"> INSTALL @lib$ + "DATELIB"
 
INPUT "What year to calculate (YYYY)? " Year%
 
PRINT '"Last Fridays in ";Year% " are on:"
FOR Month%=1 TO 12
PRINT Year% "-" RIGHT$("0" + STR$Month%, 2) "-"; \
\ FN_dim(Month%, Year%) - (FN_dow(FN_mjd(FN_dim(Month%, Year%), Month%, Year%)) + 2) MOD 7
NEXT</syntaxhighlight>
{{out}}
<pre>What year to calculate (YYYY)? 2023
 
Last Fridays in 2023 are on:
2023-01-27
2023-02-24
2023-03-31
2023-04-28
2023-05-26
2023-06-30
2023-07-28
2023-08-25
2023-09-29
2023-10-27
2023-11-24
2023-12-29</pre>
 
=={{header|Befunge}}==
Line 1,284 ⟶ 1,312:
29.11.2019
27.12.2019</pre>
 
=={{header|EasyLang}}==
<syntaxhighlight>
func leap year .
return if year mod 4 = 0 and (year mod 100 <> 0 or year mod 400 = 0)
.
func weekday year month day .
normdoom[] = [ 3 7 7 4 2 6 4 1 5 3 7 5 ]
c = year div 100
r = year mod 100
s = r div 12
t = r mod 12
c_anchor = (5 * (c mod 4) + 2) mod 7
doom = (s + t + (t div 4) + c_anchor) mod 7
anchor = normdoom[month]
if leap year = 1 and month <= 2
anchor = (anchor + 1) mod1 7
.
return (doom + day - anchor + 7) mod 7 + 1
.
mdays[] = [ 31 28 31 30 31 30 31 31 30 31 30 31 ]
proc last_fridays year . .
for m to 12
d = mdays[m]
if m = 2 and leap year = 1
d = 29
.
d -= (weekday year m d - 6) mod 7
m$ = m
if m < 10
m$ = "0" & m
.
print year & "-" & m$ & "-" & d
.
.
last_fridays 2023
</syntaxhighlight>
 
=={{header|Elixir}}==
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