Largest proper divisor of n: Difference between revisions
→{{header|Wren}}: More efficient.
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(→{{header|Wren}}: More efficient.) |
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Line 53:
System.write(" 1 ")
for (n in 2..100) {
if (n % 2 == 0) {
Fmt.write("$2d ", Int.properDivisors(n)[-1])▼
Fmt.write("$2d ", n / 2)
} else {
▲ Fmt.write("$2d ", Int.properDivisors(n)[-1])
}
if (n % 10 == 0) System.print()
}</lang>
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