Largest proper divisor of n: Difference between revisions
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→{{header|Wren}}: More efficient. |
m →{{header|Wren}}: Oops |
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Line 54:
for (n in 2..100) {
if (n % 2 == 0) {
Fmt.write("$2d ", n / 2)
} else {
Fmt.write("$2d ", Int.properDivisors(n)[-1])
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