Largest proper divisor of n: Difference between revisions
→{{header|Ruby}}: added prime check
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(→{{header|Ruby}}: added prime check) |
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</pre>
=={{header|Ruby}}==
<lang ruby>
def a(n)
return 1 if n == 1 || n.prime?
(n/2).downto(1).detect{|d| n.remainder(d) == 0}
end
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