Largest product in a grid: Difference between revisions
Added Algol 68
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=={{header|ALGOL 68}}==
<lang algol68>BEGIN # find the maximum product of 4 adjacent numbers in a row or column of a matrix #
[,]INT m = ( ( 08, 02, 22, 97, 38, 15, 00, 40, 00, 75, 04, 05, 07, 78, 52, 12, 50, 77, 91, 08 )
, ( 49, 49, 99, 40, 17, 81, 18, 57, 60, 87, 17, 40, 98, 43, 69, 48, 04, 56, 62, 00 )
, ( 81, 49, 31, 73, 55, 79, 14, 29, 93, 71, 40, 67, 53, 88, 30, 03, 49, 13, 36, 65 )
, ( 52, 70, 95, 23, 04, 60, 11, 42, 69, 24, 68, 56, 01, 32, 56, 71, 37, 02, 36, 91 )
, ( 22, 31, 16, 71, 51, 67, 63, 89, 41, 92, 36, 54, 22, 40, 40, 28, 66, 33, 13, 80 )
, ( 24, 47, 32, 60, 99, 03, 45, 02, 44, 75, 33, 53, 78, 36, 84, 20, 35, 17, 12, 50 )
, ( 32, 98, 81, 28, 64, 23, 67, 10, 26, 38, 40, 67, 59, 54, 70, 66, 18, 38, 64, 70 )
, ( 67, 26, 20, 68, 02, 62, 12, 20, 95, 63, 94, 39, 63, 08, 40, 91, 66, 49, 94, 21 )
, ( 24, 55, 58, 05, 66, 73, 99, 26, 97, 17, 78, 78, 96, 83, 14, 88, 34, 89, 63, 72 )
, ( 21, 36, 23, 09, 75, 00, 76, 44, 20, 45, 35, 14, 00, 61, 33, 97, 34, 31, 33, 95 )
, ( 78, 17, 53, 28, 22, 75, 31, 67, 15, 94, 03, 80, 04, 62, 16, 14, 09, 53, 56, 92 )
, ( 16, 39, 05, 42, 96, 35, 31, 47, 55, 58, 88, 24, 00, 17, 54, 24, 36, 29, 85, 57 )
, ( 86, 56, 00, 48, 35, 71, 89, 07, 05, 44, 44, 37, 44, 60, 21, 58, 51, 54, 17, 58 )
, ( 19, 80, 81, 68, 05, 94, 47, 69, 28, 73, 92, 13, 86, 52, 17, 77, 04, 89, 55, 40 )
, ( 04, 52, 08, 83, 97, 35, 99, 16, 07, 97, 57, 32, 16, 26, 26, 79, 33, 27, 98, 66 )
, ( 88, 36, 68, 87, 57, 62, 20, 72, 03, 46, 33, 67, 46, 55, 12, 32, 63, 93, 53, 69 )
, ( 04, 42, 16, 73, 38, 25, 39, 11, 24, 94, 72, 18, 08, 46, 29, 32, 40, 62, 76, 36 )
, ( 20, 69, 36, 41, 72, 30, 23, 88, 34, 62, 99, 69, 82, 67, 59, 85, 74, 04, 36, 16 )
, ( 20, 73, 35, 29, 78, 31, 90, 01, 74, 31, 49, 71, 48, 86, 81, 16, 23, 57, 05, 54 )
, ( 01, 70, 54, 71, 83, 51, 54, 69, 16, 92, 33, 48, 61, 43, 52, 01, 89, 19, 67, 48 )
);
INT elements = 4; # number of elements to multiply #
INT max product := - max int; # most negative integer #
INT row := 0, col := 0;
BOOL horizontal := TRUE;
FOR i FROM 1 LWB m TO 1 UPB m DO
FOR j FROM 2 LWB m TO ( 2 UPB m - elements ) + 1 DO
INT ij product := m[ i, j ] * m[ i, j + 1 ] * m[ i, j + 2 ] * m[ i, j + 3 ];
IF ij product > max product THEN
max product := ij product;
row := i;
col := j
FI
OD
OD;
FOR j FROM 2 LWB m TO 2 UPB m DO
FOR i FROM 1 LWB m TO ( 2 UPB m - elements ) + 1 DO
INT ij product := m[ i, j ] * m[ i + 1, j ] * m[ i + 2, j ] * m[ i + 3, j ];
IF ij product > max product THEN
max product := ij product;
row := i;
col := j;
horizontal := FALSE
FI
OD
OD;
print( ( "The maximum product of ", whole( elements, 0 )
, " elements: ", whole( max product, 0 )
, " is the ", IF horizontal THEN "row" ELSE "column" FI
, " of 4 numbers starting at: ", whole( row, 0 ), ", ", whole( col, 0 )
)
)
END</lang>
{{out}}
<pre>
The maximum product of 4 elements: 51267216 is the column of 4 numbers starting at: 7, 16
</pre>
=={{header|Factor}}==
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