LU decomposition: Difference between revisions
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</pre> |
</pre> |
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=={{header|Mathematica}}== |
=={{header|Mathematica}}/{{header|Wolfram Language}}== |
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<lang Mathematica>(*Ex1*)a = {{1, 3, 5}, {2, 4, 7}, {1, 1, 0}}; |
<lang Mathematica>(*Ex1*)a = {{1, 3, 5}, {2, 4, 7}, {1, 1, 0}}; |
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{lu, p, c} = LUDecomposition[a]; |
{lu, p, c} = LUDecomposition[a]; |
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