Kronecker product: Difference between revisions
m
→{{header|SuperCollider}}: second test
(Add SuperCollider example) |
m (→{{header|SuperCollider}}: second test) |
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Line 1,588:
)
<lang SuperCollider>
// to apply either of the two functions:
(
Line 1,618 ⟶ 1,620:
[ 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0 ],
[ 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0 ]
]
</pre>
And:
<lang SuperCollider>(
x = f.(
[
[ 1, 2 ],
[ 3, 4 ]
],
[
[ 0, 5 ],
[ 6, 7 ]
]
)
)
</lang>
returns:
<pre>
[
[ 0, 5, 0, 10 ],
[ 6, 7, 12, 14 ],
[ 0, 15, 0, 20 ],
[ 18, 21, 24, 28 ]
]
</pre>
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