Knapsack problem/Continuous: Difference between revisions
Content added Content deleted
SqrtNegInf (talk | contribs) m (→{{header|Perl 6}}: fixed 'new' method) |
mNo edit summary |
||
| Line 159: | Line 159: | ||
<lang APL> |
<lang APL> |
||
⍝ Data |
⍝ Data |
||
Items←'beef' 'pork' 'ham' 'greaves' 'flitch' 'brawn' 'welt' 'salami' 'sausage' |
|||
Weights←3.8 5.4 3.6 2.4 4 2.5 3.7 3 5.9 |
|||
Prices←36 43 90 45 30 56 67 95 98 |
|||
⍝ Solution |
⍝ Solution |
||
Order←⍒Worth←Prices÷Weights ⍝ 'Worth' is each item value for 1 kg. |
|||
diff←{¯1↓(⍵,0)-0,⍵} ⍝ 'diff' between each item and the prev item (the inverse of '+\'). |
diff←{¯1↓(⍵,0)-0,⍵} ⍝ 'diff' between each item and the prev item (the inverse of '+\'). |
||
Filter←×Selected←diff 15⌊+\Weights[Order] ⍝ 'Selected' weights totaling 15kg, others 0. |
|||
Table←⊃{⍺,⍪⍵}/Items Weights Selected[⍋Order] |
|||
Take←Filter[⍋Order]/[1]Table |
|||
TotalCost←+/Prices×Selected[⍋Order]÷Weights |
|||
</lang> |
</lang> |
||