Integer sequence: Difference between revisions

From Rosetta Code
Content added Content deleted
(→‎{{header|C}}: Variant using for loop)
(+CL, more Haskell)
Line 45: Line 45:
return 0;
return 0;
}</lang>
}</lang>

=={{header|Common Lisp}}==

<lang lisp>(loop for i from 1 do (print i))</lang>


=={{header|Perl}}==
=={{header|Perl}}==
Line 56: Line 60:
=={{header|Haskell}}==
=={{header|Haskell}}==
<lang haskell>mapM_ print [1..]</lang>
<lang haskell>mapM_ print [1..]</lang>

Or less imperatively:

<lang haskell>(putStr . unlines . map show) [1..]</lang>

Revision as of 00:38, 13 February 2011

Integer sequence is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

Create a program that, when run, would display all integers from 1 to ∞ (or any relevant implementation limit) if given enough time.

BASIC

<lang basic>5 LET A = 0 10 LET A = A + 1 20 PRINT A 30 GOTO 10</lang>

C

<lang c>#include <stdio.h>

int main() {

 uint_32 i = 0;
 while(1)
 {
   printf("%u\n", ++i);
 }
 return 0;

}</lang>

Alternatively: <lang c>#include <stdio.h>

int main() {

 for(uint i = 1; 1; i++)
   printf("%d\n", i);
 return 0;

}</lang>

C++

<lang cpp>#include <iostream>

int main() {

 uint_32 i = 0;
 while(true)
 {
   std::cout << ++i << std::endl;
 }
 return 0;

}</lang>

Common Lisp

<lang lisp>(loop for i from 1 do (print i))</lang>

Perl

<lang perl>my $i = 0; while(1) {

 print ++$i . "\n";

} </lang>

Haskell

<lang haskell>mapM_ print [1..]</lang>

Or less imperatively:

<lang haskell>(putStr . unlines . map show) [1..]</lang>