Integer roots: Difference between revisions
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→{{header|Haskell}}: Avoided shadowing of `sequence` (standard Traversable function name)
m (→{{header|Haskell}}: (applied hindent)) |
m (→{{header|Haskell}}: Avoided shadowing of `sequence` (standard Traversable function name)) |
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Line 311:
{{trans|Python}}
<lang haskell>root :: Integer -> Integer -> Integer
root a b = findAns
where
a1 = a - 1
findAns (x:xs@(y:z:_))
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