Hourglass puzzle: Difference between revisions
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At time t = 14 , flip hourglass 7 |
At time t = 14 , flip hourglass 7 |
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At time t = 16 , flip hourglass 4 end = 9</pre> |
At time t = 16 , flip hourglass 4 end = 9</pre> |
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If interim-flips are allowed I think the following is shorter, just that I wish I knew how to implement it .. |
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<lang perl6>t x(4) y(7) |
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0 |
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4 flip record = 0 |
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7 flip flip record +=3 |
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10 stop flip record +=3 |
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13 stop record +=3</lang> |
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=={{header|REXX}}== |
=={{header|REXX}}== |
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