Hourglass puzzle: Difference between revisions

{{draft task}}

[[Category:Puzzles]]

[[Category:Games]]

 

Implemented as a 1-player game.

 

=={{header|Julia}}==

Implemented as a game solver rather than as a game with user input.

gcd(hourglasses) in hourglasses && !(1 in hourglasses) && throw("Hourglasses fail sanity test (not relatively prime enough)")

flippers, series = deepcopy(hourglasses), Int[]

i, j = euclidean_hourglassflipper([5, 7, 31], 36)

println("Use hourglasses from step $i to step $j (inclusive) to sum 36 using [5, 7, 31]")

<pre>

Flip an hourglass every time it runs out of grains, and note the interval in time.

=={{header|Logo}}==

tested with FMSlogo

to bb

Make "small_capacity 4

 

 

 

=={{header|Python}}==

There isn't much of a task description as I write this, but, here goes...

 

t4 = 0

while t4 < 10_000:

""")

 

{{out}}

flipping the remaining sand in the 7 hour glass when the 4 hour glass ends.</pre>

 

 

=={{header|REXX}}==

{{trans|Python}}

/*──────────────────────────────────── four and seven minute sandglasses. */

t4= 0

say "Turn over both sandglasses (at the same time) and continue"

say "flipping them each when the sandglasses individually run down"

say "whereupon the seven-minute glass is immediately placed on its"

say

say "You can measure 9 minutes by flipping the four-minute glass"

say "glass when the four-minute glass ends."

say

{{out|output|text=&nbsp; when using the internal default input:}}

<pre>

Turn over both sandglasses (at the same time) and continue

flipping them each when the sandglasses individually run down

whereupon the seven-minute glass is immediately placed on its

 

You can measure 9 minutes by flipping the four-minute glass

once, then flipping the remaining sand in the seven-minute

glass when the four-minute glass ends.

</pre>