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Horizontal sundial calculations: Difference between revisions
→{{header|C}}: Adding C#
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Line 189:
return 0;
}</lang>
=={{header|C sharp|C#}}==
<lang csharp>using System;
namespace RosettaCode
{
internal sealed class Program
{
private static void Main()
{
Func<double> getDouble = () => Convert.ToDouble(Console.ReadLine());
double h = 0, lat, lng, lme, slat, hra, hla;
Console.Write("Enter latitude => ");
lat = getDouble();
Console.Write("Enter longitude => ");
lng = getDouble();
Console.Write("Enter legal meridian => ");
lme = getDouble();
slat = Math.Sin(lat*2*Math.PI/360);
Console.WriteLine("\n sine of latitude: {0:0.000}", slat);
Console.WriteLine(" diff longitude: {0:0.000}\n", lng-lme);
Console.WriteLine("Hour, sun hour angle, dial hour line angle from 6am to 6pm");
for (h = -6; h<6; h++)
{
hra = 15*h;
hra -= lng-lme;
hla = Math.Atan(slat*Math.Tan(hra*2*Math.PI/360))*360/(2*Math.PI);
Console.WriteLine("HR= {0,7:0.000}; HRA {1,7:0.000}; HLA= {2,7:0.000}", h, hra, hla);
}
}
}
}</lang>
=={{header|D}}==
{{trans|Python}}
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