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Function prototype: Difference between revisions
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void main() {}</lang>
=={{header|J}}==
J assumes an unknown name is a verb of infinite rank. Rank determines the frames on which the verb executes. As the demonstration shows, changing the rank, assigning the rank before the verb is used in other definitions affects the result. We could, of course, play other games by changing the unknown name from verb to another part of speech.
<lang J>
NB. j assumes an unknown name f is a verb of infinite rank
NB. The verb g makes a table.
g=: f/~
NB. * has rank 0
f=: *
NB. indeed, make a multiplication table
f/~ i.5
0 0 0 0 0
0 1 2 3 4
0 2 4 6 8
0 3 6 9 12
0 4 8 12 16
NB. g was defined as if f had infinite rank.
g i.5
0 1 4 9 16
NB. f is known to have rank 0.
g=: f/~
NB. Now we reproduce the table
g i.5
0 0 0 0 0
0 1 2 3 4
0 2 4 6 8
0 3 6 9 12
0 4 8 12 16
NB. change f to another rank 0 verb
f=: +
NB. and construct an addition table
g i.5
0 1 2 3 4
1 2 3 4 5
2 3 4 5 6
3 4 5 6 7
4 5 6 7 8
NB. f is multiplication at infinite rank
f=: *"_
NB. g, however, has rank 0
g i.5
0 0 0 0 0
0 1 2 3 4
0 2 4 6 8
0 3 6 9 12
0 4 8 12 16
</lang>
=={{header|PARI/GP}}==
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