Function frequency: Difference between revisions

From Rosetta Code
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(Go solution)
Line 16:
"io/ioutil"
"os"
"sort"
)
 
Line 44 ⟶ 45:
return true
})
cs := make(calls, 0, len(m))
for k, v := range m {
fmt.Printlncs = append(vcs, &call{k, v})
}
sort.Sort(cs)
}</lang>
for i, c := range cs {
fmt.Printf("%-20s %4d\n", c.expr, c.count)
if i == 9 {
break
}
}
}
 
type call struct {
1 expr string
count int
}
type calls []*call
 
func (c calls) Len() int { return len(c) }
func (c calls) Swap(i, j int) { c[i], c[j] = c[j], c[i] }
func (c calls) Less(i, j int) bool { return c[i].count > c[j].count }</lang>
Output, when run on source code above:
<pre>
len 3
4 fmt.Println 3
1 string
f.Offset 2
1 a.Pos
make 2
1 ast.Inspect
fmt.Printf 1
1 ioutil.ReadFile 1
1 len
a.Pos 1
2 f.Offset
string 1
1 token.NewFileSet
skeys byron 81> 1
1 ce.Pos
append 1
1 make
1 fs.File
1 parser.ParseFile
</pre>
 
=={{header|PicoLisp}}==
<lang PicoLisp>(let Freq NIL

Revision as of 19:09, 2 November 2011

Function frequency is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

Display - for a program or runtime environment (whatever suites the style of your language) - the top ten most frequently occurring functions.

This is a static analysis: The question is not how often each function is actually executed at runtime, but how often it is used by the programmer.

Go

Only crude approximation is currently easy in Go. The following parses source code, looks for function call syntax (an expression followed by an argument list) and prints the expression. <lang go>package main

import (

   "fmt"
   "go/ast"
   "go/parser"
   "go/token"
   "io/ioutil"
   "os"
   "sort"

)

func main() {

   if len(os.Args) != 2 {
       fmt.Println("usage ff <go source filename>")
       return
   }
   src, err := ioutil.ReadFile(os.Args[1])
   if err != nil {
       fmt.Println(err)
       return
   }
   fs := token.NewFileSet()
   a, err := parser.ParseFile(fs, os.Args[1], src, 0)
   if err != nil {
       fmt.Println(err)
       return
   }
   f := fs.File(a.Pos())
   m := make(map[string]int)
   ast.Inspect(a, func(n ast.Node) bool {
       if ce, ok := n.(*ast.CallExpr); ok {
           start := f.Offset(ce.Pos())
           end := f.Offset(ce.Lparen)
           m[string(src[start:end])]++
       }
       return true
   })
   cs := make(calls, 0, len(m))
   for k, v := range m {
       cs = append(cs, &call{k, v})
   }
   sort.Sort(cs)
   for i, c := range cs {
       fmt.Printf("%-20s %4d\n", c.expr, c.count)
       if i == 9 {
           break
       }
   }

}

type call struct {

   expr  string
   count int

} type calls []*call

func (c calls) Len() int { return len(c) } func (c calls) Swap(i, j int) { c[i], c[j] = c[j], c[i] } func (c calls) Less(i, j int) bool { return c[i].count > c[j].count }</lang> Output, when run on source code above:

len                     3
fmt.Println             3
f.Offset                2
make                    2
fmt.Printf              1
ioutil.ReadFile         1
a.Pos                   1
string                  1
skeys byron 81>         1
append                  1

PicoLisp

<lang PicoLisp>(let Freq NIL

  (for "L" (filter pair (extract getd (all)))
     (for "F"
        (filter atom
           (fish '((X) (or (circ? X) (getd X)))
              "L" ) )
        (accu 'Freq "F" 1) ) )
  (for X (head 10 (flip (by cdr sort Freq)))
     (tab (-7 4) (car X) (cdr X)) ) )</lang>

Output:

quote   310
car     236
cdr     181
setq    148
let     136
if      127
and     124
cons    110
cadr     80
or       76